Torgny Tholerus wrote:
An ultrafinitist comment to this: ====== You can add this complementary sequence to the end of the list. That will make you have a list with this complementary sequence included. But then you can make a new complementary sequence, that is not inluded. But you can then add this new sequence to the end of the extended list, and then you have a bijection with this new sequence also. And if you try to make another new sequence, I will add that sequence too, and this I will do an infinite number of times. So you will not be able to prove that there is no bijection... ====== What is wrong with this conclusion?You'd have to insert the new sequence in the beginning, as there is no "end of the list".
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