Re: Quantum accident survivor
I mean the absolutely exact same David Kwinter or Eric Cavalcanti as
was the moment before.
<see below for further comment>
On Wednesday, November 5, 2003, at 01:33 PM, Eric Cavalcanti wrote:
>
> What do you mean by *entirely equal*?
>
> ----- Original Message -----
> From: "David Kwinter" <david.domain.name.hidden>
> To: <everything-list.domain.name.hidden>
> Sent: Thursday, November 06, 2003 5:19 AM
> Subject: Re: Quantum accident survivor
>
>
>> On Tuesday, November 4, 2003, at 10:47 AM, Eric Cavalcanti wrote:
>>>
>>> Let me stress this point: *I am, for all practical purposes,
>>> one and only one specific configuration of atoms in a
>>> specific universe. I could never say that ' I ' is ALL the
>>> copies, since I NEVER experience what the other copies
>>> experience. The other copies are just similar
>>> configurations of atoms in other universes, which shared
>>> the same history, prior to a given point in time.*
>>
>>
>> I would consider these other copies entirely equal to myself IF AND
>> ONLY IF they are succeeding RSSA observer-moments.
>>
>>
>>
>> Glossary references : )
>>
>> RSSA - The Relative Self-Sampling Assumption, which says that you
>> should
>> consider your next observer-moment to be randomly sampled from among
>> all
>> observer-moments which come immediately after your current
>> observer-moment
>> and belong to the same observer.
>>
>
>
>
> In a materialistic framework, ' I ' am a bunch of atoms. These atoms
> happen to constitute a system that has self-referential qualities that
> we call consciousness. If it happened that these atoms temporarily
> (like in a coma or anesthesy) or permanently (death) lose this quality,
> so will ' I '.
I respectfully disagree - parallel universes are equally REAL- you will
still be you! Quantum branches stem from the same exact atoms in the
versions of us that die in tons of possible accidents everyday.
Received on Fri Nov 07 2003 - 12:23:57 PST
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