Re: Measure of the prisoner

From: <GSLevy.domain.name.hidden>
Date: Mon, 28 Aug 2000 13:22:21 EDT

In a message dated 08/28/2000 8:23:06 AM Pacific Daylight Time,
smitra.domain.name.hidden writes:

> The probability P that the prisoner finds himself in the ``simulated´´
> universe is thus given as:
>
> P = (t'/t+m3/m1 )/(1+t'/t+m3/m1)

This is the probability that observer B in the real world observes observer A
in a simulated world, given that observer B is in the real world (though I
don't quite understand the purpose of m3). In this sense it is a conditional
probability. But what would the probability of being in the simulated world
be for an observer in the simulated world? This is the conditional
probability of observing oneself being there given that one is there and is
equal to 1. Similarly the probability of observing oneself in the real world
given that one is in the real world is 1. Probability lies on the eyes of the
beholder. Be careful when you talk about probability and measure in absolute
terms.

George Levy
Received on Mon Aug 28 2000 - 10:34:52 PDT