Re: The seven step series

From: ronaldheld <RonaldHeld.domain.name.hidden>
Date: Tue, 28 Jul 2009 03:51:54 -0700 (PDT)

Bruno:
 I meant the mathematical formalism you are teaching us. When we
eventually get to the UDA steps, I wil be better able to do that
assessment.
                                                      Ronald

On Jul 27, 1:27 pm, Bruno Marchal <marc....domain.name.hidden> wrote:
> On 27 Jul 2009, at 16:07, ronaldheld wrote:
>
>
>
> >   I am following, but have not commented, because there is nothing
> > controversal.
>
> Cool. Even the sixth first steps of UDA?
>
>
>
> >   When you are done, can your posts be consolidated into a paper or a
> > document that can be read staright through?
>
> I should do that.
>
> Bruno
>
>
>
>
>
> > On Jul 23, 9:28 am, Bruno Marchal <marc....domain.name.hidden> wrote:
> >> On 23 Jul 2009, at 15:09, m.a. wrote:
>
> >>> Bruno,
> >>>             Yes, yours and Brent's explanations seem very clear. I
> >>> hate to ask you to spell things out step by step all the way, but I
> >>> can tell you that when I'm confronted by a dense hedge or clump of
> >>> math symbols, my mind refuses to even try to disentangle them and
> >>> reels back in terror. So I beg you to always advance in baby steps
> >>> with lots of space between statements. I want to assure you that I'm
> >>> printing out all of your 7-step lessons and using them for study and
> >>> reference. Thanks for your patience,   m.a.
>
> >> Don't worry, I understand that very well. And this illustrates also
> >> that your "despair" is more psychological than anything else. I have
> >> also abandoned the study of a mathematical book until I realize that
> >> the difficulty was more my bad eyesight than any conceptual
> >> difficulties. With good spectacles I realize the subject was not too
> >> difficult, but agglomeration of little symbols can give a bad
> >> impression, even for a mathematician.
>
> >> I will make some effort, tell me if my last post, on the relation
>
> >>       (a^n) * (a^m) = a^(n + m)
>
> >> did help you.
>
> >> You are lucky to have an infinitely patient teacher. You can ask any
> >> question, like "Bruno,
>
> >> is (a^n) * (a^m) the same as a^n times a^m?"
> >>   Answer: yes, I use often "*", "x", as shorthand for "times", and I
> >> use "(" and ")" as delimiters in case I fear some ambiguity.
>
> >> Bruno
>
> >>> -- Original Message -----
> >>> From: Bruno Marchal
> >>> To: everything-list.domain.name.hidden
> >>> Sent: Wednesday, July 22, 2009 12:20 PM
> >>> Subject: Re: The seven step series
>
> >>> Marty,
>
> >>> Brent wrote:
>
> >>> On 21 Jul 2009, at 23:24, Brent Meeker wrote:
>
> >>>> Take all strings of length 2
> >>>> 00             01                   10               11
> >>>> Make two copies of each
> >>>> 00      00      01      01      10      10      11      11
> >>>> Add a 00 to the first and a 01 to the second
> >>>> 000    001      010   011      100   101   110      111
> >>>> and you have all strings of length 3.
>
> >>> Then you wrote
>
> >>>> I can see where adding 0 to the first and 1 to the second gives 000
> >>>> and 001 and I think I see how you get 010 but the rest of the
> >>>> permutations don't seem obvious to me. P-l-e-a-s-e  explain,  Best,
>
> >>>>                                                                                                                                                                                                                                 m
> >>>> . (mathematically hopeless)  a.
>
> >>> Let me rewrite Brent's explanation, with a tiny tiny tiny  
> >>> improvement:
>
> >>> Take all strings of length 2
> >>> 00
> >>> 01
> >>> 10
> >>> 11
> >>> Make two copies of each
>
> >>> first copy:
> >>> 00
> >>> 01
> >>> 10
> >>> 11
>
> >>> second copy
> >>> 00
> >>> 01
> >>> 10
> >>> 11
>
> >>> add a 0 to the end of the strings in the first copy, and then add a
> >>> 1  to the end of the strings in the second copy:
>
> >>> first copy:
> >>> 000
> >>> 010
> >>> 100
> >>> 110
>
> >>> second copy
> >>> 001
> >>> 011
> >>> 101
> >>> 111
>
> >>> You get all 08 elements of B_3.
>
> >>> You can do the same reasoning with the subsets. Adding an element to
> >>> a set multiplies by 02 the number of elements of the powerset:
>
> >>> Exemple. take a set with two elements {a, b}. Its powerset is {{ }
> >>> {a} {b} {a, b}}. How to get all the subset of {a, b, c} that is the
> >>> set coming from adding c to {a, b}.
>
> >>> Write two copies of the powerset of {a, b}
>
> >>> { }
> >>> {a}
> >>> {b}
> >>> {a, b}
>
> >>> { }
> >>> {a}
> >>> {b}
> >>> {a, b}
>
> >>> Don't add c to the set in the first copy, and add c to the sets in
> >>> the second copies. This gives
>
> >>> { }
> >>> {a}
> >>> {b}
> >>> {a, b}
>
> >>> {c}
> >>> {a, c}
> >>> {b, c}
> >>> {a, b, c}
>
> >>> and that gives all subsets of {a, b, c}.
>
> >>> This is coherent with interpreting a subset {a, b} of a set {a, b,
> >>> c}, by a string like 110, which can be conceived as a shortand for
>
> >>> Is a in the subset?   YES, thus 1
> >>> Is b in the subset?   YES thus  1
> >>> Is c in the subset?    NO thus   0.
>
> >>> OK?
>
> >>> You say also:
>
> >>>> The example of Mister X only confuses me more.
>
> >>> Once you understand well the present post, I suggest you reread the
> >>> Mister X examples, because it is a key in the UDA reasoning. If you
> >>> still have problem with it, I suggest you quote it, line by line,
> >>> and ask question. I will answer (or perhaps someone else).
>
> >>> Don't be afraid to ask any question. You are not mathematically
> >>> hopeless. You are just not familiarized with reasoning in math. It
> >>> is normal to go slowly. As far as you can say "I don't understand",
> >>> there is hope you will understand.
>
> >>> Indeed, concerning the UDA I suspect many in the list cannot say "I
> >>> don't understand", they believe it is philosophy, so they feel like
> >>> they could object on philosophical ground, when the whole point is
> >>> to present a deductive argument in a theory. So it is false, or you
> >>> have to accept the theorem in the theory. It is a bit complex,
> >>> because it is an "applied theory". The mystery are in the axioms of
> >>> the theory, as always.
>
> >>> So please ask *any* question. I ask this to everyone. I am intrigued
> >>> by the difficulty some people can have with such reasoning (I mean
> >>> the whole UDA here). (I can understand the shock when you get the
> >>> point, but that is always the case with new results: I completely
> >>> share Tegmark's idea that our brain have not been prepared to
> >>> have    any intuition when our mind try to figure out what is behind
> >>> our local neighborhood).
>
> >>> Bruno
>
> >>>http://iridia.ulb.ac.be/~marchal/
>
> >>http://iridia.ulb.ac.be/~marchal/-Hide quoted text -
>
> >> - Show quoted text -
>
> http://iridia.ulb.ac.be/~marchal/- Hide quoted text -
>
> - Show quoted text -
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Received on Tue Jul 28 2009 - 03:51:54 PDT

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