Re: Seven Step Series

From: Brent Meeker <meekerdb.domain.name.hidden>
Date: Thu, 23 Jul 2009 09:15:59 -0700

m.a. wrote:
> Hi Bruno,
> Yes, this is all clear to me. But when I try to put it
> into practice, confusion reigns. (See bottom of page.) By the way,
> because I'm printing out your lessons and often need to refer back to
> specific ones, it becomes confusing when you append lessons to posts
> with different subjects. Thanks, marty a.
>
>
>
> ----- Original Message -----
> *From:* Bruno Marchal <mailto:marchal.domain.name.hidden>
...
> Just a question to proceed later: do you agree that
>
> (a*a*a*a)/ (a*a*a) = (a*a*a*a) times 1/(a*a*a)
>
> with this and what I said, you can guess that:
>
> a^n * a^(-m) = a^(n-m)
>
> Again, verify this on simple example of your own.
>
> *OK: If a=10 and n=3 and m=4 Following the formula above
> "a^n * a^(-m)" ,I get as the first half of the equation:*
> **
> *10^3 * 10/4 = 1000 x 2.5= 2500 but for the second half
> "a^(n-m) I get:*
> **
> *10^(n-m)= 10^ -1= 10/1*
> **
> *which of course makes no sense at all. Where did I go wrong?*

10^(-4) is not equal to 10/4, it's equal to 1/(10^4) or 0.0001

Brent

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Received on Thu Jul 23 2009 - 09:15:59 PDT

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