# Re: The seven step series

From: m.a. <marty684.domain.name.hidden>
Date: Wed, 22 Jul 2009 23:28:57 -0400

Going a step further... (see below)

----- Original Message -----
From: "Brent Meeker" <meekerdb.domain.name.hidden>
To: <everything-list.domain.name.hidden>
Sent: Wednesday, July 22, 2009 12:57 PM
Subject: Re: The seven step series

>
> m.a. wrote:
>> Hi Brent,
>> I really appreciate the help and I hate to impose on
>>
>> ----- Original Message -----
>> From: "Brent Meeker" <meekerdb.domain.name.hidden
>> <mailto:meekerdb.domain.name.hidden>>
>> To: <everything-list.domain.name.hidden
>> <mailto:everything-list.domain.name.hidden>>
>> Sent: Tuesday, July 21, 2009 5:24 PM
>> Subject: Re: The seven step series
>>
>> >
>> > Take all strings of length 2
>> > 00 01 10 11
>> > Make two copies of each
>> > 00 00 01 01 10 10 11 11
>>
>> > Add a 00 to the first and a 01 to the second
>> > 000 001 010 011 100 101 110 111
>> > and you have all strings of length 3.
>> *I can see where adding 0 to the first and 1 to the second gives 000 and
>> 001 and I think I see how you get 010 but the rest of the permutations
>> don't seem obvious to me. P-l-e-a-s-e explain, Best,*
>> **
>>
>>
They aren't permutations. They're just sticking a 0 or 1 on the end. One copy
> of 01 becomes 010 and the other become 011.

Then I assume the next step would be making two copies of each of those:

000 000 001 001 010 010 011 011 100 100 101 101 110 110 111 111

...and sticking a 0 or 1 at the end:

0000 0001 0010 0011 0100 0101 0110 0111 1000 1001 1010 1011 1100 1101 1110 1111

and this is the binary sequence of length 4.

How do these translate into ordinary numerals? 1,2,3,4...

>
> Brent
>
> >
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Received on Wed Jul 22 2009 - 23:28:57 PDT

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