Hal,
I went back and reviewed some of your old postings. My interpretation
of your system was closer to the mark than I'd suspected!
I think enumeration via inconsistency can be equivalent to enumeration
by incompleteness... depending on exactly how things are defined.
Enumeration by inconsistency seems more intuitive to me: inconsistency
can be readily detected (derive P&~P), whereas incompleteness cannot.
--Abram
On Mon, Dec 29, 2008 at 6:47 PM, Hal Ruhl <HalRuhl.domain.name.hidden> wrote:
>
> Hi Abram:
>
> My sentence structure could have been better. The Nothing(s) encompass no
> distinction but need to respond to the stability question. So they have an
> unavoidable necessity to encompass this distinction. At some point they
> spontaneously change nature and become Somethings. The particular Something
> may also be incomplete for the same or some other set of unavoidable
> questions. This is what keeps the particular incompleteness trace going.
>
> In this regard also see my next lines in that post:
>
> "The N(k) are thus unstable with respect to their "empty" condition. They
> each must at some point spontaneously "seek" to encompass this stability
> distinction. They become evolving S(i) [call them eS(i)]."
>
> I have used this Nothing to Something transformation trigger for many years
> in other posts and did not notice that this time the wording was not as
> clear as it could have been.
>
> However, this lack of clarity seems to have been useful given your
> discussion of inconsistency driven traces. I had not considered this
> before.
>
> Yours
>
> Hal
>
> -----Original Message-----
> From: everything-list.domain.name.hidden
> [mailto:everything-list.domain.name.hidden] On Behalf Of Abram Demski
> Sent: Monday, December 29, 2008 12:59 AM
> To: everything-list.domain.name.hidden
> Subject: Re: Revisions to my approach. Is it a UD?
>
>
> Hal,
>
> I do not understand why the Nothings are fundamentally incomplete. I
> interpreted this as inconsistency, partly due to the following line:
>
> "5) At least one divisor type - the Nothings or N(k)- encompass no
> distinction but must encompass this one. This is a type of incompleteness."
>
> If they encompass no distinctions yet encompass one, they are
> apparently inconsistent. So what do you mean when you instead assert
> them to be incomplete?
>
> --Abram
>
>
>
> >
>
--
Abram Demski
Public address: abram-demski.domain.name.hidden
Public archive: http://groups.google.com/group/abram-demski
Private address: abramdemski.domain.name.hidden
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Received on Fri Jan 02 2009 - 10:01:24 PST