Re: Cantor's Diagonal

From: Russell Standish <lists.domain.name.hidden>
Date: Mon, 17 Dec 2007 10:10:01 +1100

On Sun, Dec 16, 2007 at 04:49:34AM -0500, Daniel Grubbs wrote:

Cantor's argument only works by finding a number that satisfies the
criteria for inclusion in the list, yet is nowhere to be found in the
list.

In your first case, the number (1,1,1,1...) is not a natural number,
since it is infinite. In the second case, (0,0,0,...) is a natural
number, but is also on the list (at infinity).

Therefore Cantor's argument doesn't work in these cases.

Cheers

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Received on Sun Dec 16 2007 - 18:09:54 PST